Consider 2 equal light sources that continue to emit a consistent stream of photons as they rotate around a stationary Centre Of Mass (C.O.M.) inclined at 45 degrees and these streams travel at the speed of light, in a straight line without deviation or obstruction, from the point of emission to the Observer.

Newtonian Domain

In this model there are no (1) small sizes, (2) great speeds or (3) huge masses involved to allow the projections to be scaled proportionally in a 3D Euclidean space that represents thepaths of current and already emitted photons at a discrete instance in time. The only divergence from a true Euclidean representation is made by measuring the distances traveled off the line directly from the C.O.M. to the Observer, to allow for comparison with relativistic constructs based on a C.O.M frame.While time is used for all x, y and z axis measurements the actual time of the discrete instance being represented in this frame is t=0.

Methodology

The distance between the observer and the stationary C.O.M, = 2 * Pi * r where r is the radius of rotation of the 2 sources. The time taken for the source to rotate through one quarter = (2 * Pi * r)/4. This mapping only shows emitted photons that are still active at the time the observation is made and, during a period of one complete rotation, all these currently active photons will eventually be observed at a stationary observation point.

If a photon was emitted from a rotating source at point 1,0 and the source completed one complete rotation in the time the photon took to travel to the observer at 1,4 the source will be back at point 1,0 and a line of photons will lead from the point 1,0 to the observer at point 1,4 at t=0. When the initial source rotated through one quarter it came to point 4,0 and emitted a photon that would travel from 4,0 to point 4,3 in the remaining 3 quarters before the source arrived back at 1,0 at t=0. After another quarter the source would be at point 3,0 and a photon travelling straight to the observer would have traveled another 2 quarters and be located at position 3,2 at the time the original photon sent from point 1,0 arrived at the observer at t=0. After a third quarter the source would be location at 2,0 and the photon emitted would travel to point 2,1 at the time the observation was made at t=0.

Consequently a stream of photons emitted continually from a rotating source at point 3,0 after one rotation will have a path at t=0 that arrives at the observation point at 3,4 and leads back through points 2,3 and 1,2 and 4,1 to the current location of the source at point 3,0 all at the same instance in time.

SHIFT Determination method

The wavelength shift is determined by comparing the discrete length of each light path for each quarter shown in the Top or Side Elevation with the length of a straight quarter and determined that quarters with paths longer than this should be drawn in red to indicate that the source was moving away during that quarter and subsequently any quarters shorter than this are drawn in blue to indicate that the source was moving closer during that quarter.

SHIFT Consolidation methods

(1) Quarterly via Top and Side Elevations (x & y or x & z axis). The length of discrete red and blue lines are added up for each quarter and the percentages of red vs blue lengths are plotted for each quarter and displayed in a percent area chart. The percentage of blue lines goes up from 20 to 30 during the 4 quarters and theaverage percentages were 25% for blue and 75% for redover the Complete Rotation path. 2 groups of 3 consecutive eights (6/8) appear in the 4 quarters that give ratios of red to blue at 100% red with the remaining quarter (2 eights) comprising 2 dominantly blue but never 100% blue areas and the first 1/3 of the first quarter where the ratio was close to 50%. The sum of x, y or x, z shift lengths does not reflect two equal sources rotating around a stationary C.O.M.

(2) Complete Rotation via the End Elevation (x & y & z axis). The length of the discrete red and blue lines are added up and theaverage percentage of the sum of both blue and red lines is 50 percent.